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IAlgebra

Free · Designed for iPad

click get The App provides users with a learning platform to explore and solve algebra f(x) exercises. In each step of problem solving, by selecting the mathematical operation provided by the App, users can complete the problem-solving in exploration and learning like a driver controlling the steering wheel, master the concept of algebra in the integration of knowledge and action, and gain the ability to use concepts and knowledge to solve problems. If you want the answer, you can use a group of Ai. If you want the ability, you can try IA to make carbon-based life smarter! Not GPUs. App 提供用户一个探索求解代数f(x)习题的学习平台。在解题的每一步,通过选择App提供的数学操作,用户如车手操控方向盘般,在探索学习中完成解题, 在知行合一中掌握代数的概念,获得运用概念与知识解决问题的能力。你想要答案,可以用一众Ai,你想要能力,可以试试IA,让碳基生命更智能!而不是GPU们。

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1. (a+b-c)(a-b+c) =(a+(b-c))(a-(b-c)) 2. a()+b() remove parentheses and merge similar terms 3. Calculate the value of the independent variable of the function, such as f(1/3+1/6)+f(1/3-1/6)=f(1/3)f1/6), get f(1/2)+f(1/6)=f(1/3)f1/6 4. Move the terms of various equations together and combine the similar terms. 5. Calculate the value of the root 6. Calculate the value of the discrimination formula of the root 7. Simplify the result of simplified (a+b)^2 8. Simplify the result of multiplying same algebraic formula on both sides of the equation 9. Reduce the equations/inequalities generated by retaining intermediate calculation results 10. a/b>n>0, directly use the relevant properties of a/b>0, support n>a>=0, n>b>0 11. Add the equality u=(x+1)/(x-1) when making an introduction to the classification of log_a (x+1)/(x-1) > 1 12. Support f(f(x)) as the usage of replaceing unknown, so that t=f(x) 13. Input and execute, no need to click the selection again. 14. Provide a vertical list display of existing equations/inequalities 15. Click on the color topic to see the explanation of relevant concepts. 16. Other errors and bugs: iPad input interception, the operation does not match its interpretation, and the standard judgment of quadratic equations is not strict. 1. (a+b-c)(a-b+c) =(a+(b-c))(a-(b-c)) 2. a()+b()去括号并合并同类项 3. 计算函数自变量的值,例如f(1/3+1/6)+f(1/3-1/6)=f(1/3)f1/6),得f(1/2)+f(1/6)=f(1/3)f1/6 4. 对各类方程一并移项并合并同类项 5. 计算根的值 6. 计算根的判别式的值 7. 简化(a+b)^2的结果 8. 简化等式两边同乘代数式的结果 9. 减少保留中间计算结果产生的等式/不等式 10. a/b>n>0, 直接使用a/b>0 的相关性质,支持 n>a>=0, n>b>0 11. 对 log_a (x+1)/(x-1) > 1 做分类导论时增加换元u=(x+1)/(x-1) 12. 支持f(f(x))做还元的用法,令t=f(x) 13. 输入即可执行,不需要再点选择项 14. 提供已有等式/不等式的垂直列表显示 15. 点击彩色题目可看相关概念解释 16. 其它错误与bug: ipad 输入拦截,操作项与其解释不匹配,二次方程标准型判定不严格

The developer, 斌 朱, indicated that the app’s privacy practices may include handling of data as described below. For more information, see the developer’s privacy policy .

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    The developer does not collect any data from this app.

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    • Seller
      • 斌 朱
    • Size
      • 55.1 MB
    • Category
      • Education
    • Compatibility
      Requires iOS 15.0 or later.
      • iPhone
        Requires iOS 15.0 or later.
      • iPad
        Requires iPadOS 15.0 or later.
      • iPod touch
        Requires iOS 15.0 or later.
      • Mac
        Requires macOS 12.0 or later and a Mac with Apple M1 chip or later.
      • Apple Vision
        Requires visionOS 1.0 or later.
    • Languages
      • English
    • Age Rating
      4+
    • Copyright
      • © development independently